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CalibratePhysics

15.7

Atomic Nucleus

Structure of Atoms and Nuclei · Maharashtra HSC

Theory

Constituents of a nucleus

  • The nucleus is made of subatomic particles called protons and neutrons, together called nucleons.
  • The proton is positively charged, the magnitude of its charge being equal to that of the electron's charge; its mass is about 18361836 times the mass of an electron. The neutron is electrically neutral and its mass is nearly the same as the proton's but slightly higher.
  • The number of protons is the atomic number ZZ, which also equals the number of electrons in the neutral atom, so the atom as a whole is electrically neutral. The number of neutrons is NN.
  • The total number of nucleons is the mass number A=Z+NA = Z + N; it determines the mass of the nucleus and of the atom.
  • A nuclide is written ZAX {}^{A}_{Z}\text{X}: hydrogen 11H {}^{1}_{1}\text{H}, carbon 612C {}^{12}_{6}\text{C}, oxygen 816O {}^{16}_{8}\text{O}.
  • Chemical properties are decided by the number of electrons, i.e. by ZZ alone.

Isotopes, isobars and isotones

  • The number of protons and electrons in the atoms of a given element is fixed, but the number of neutrons can vary. Hydrogen can have zero, one or two neutrons, giving 11H {}^{1}_{1}\text{H} (hydrogen), 12H {}^{2}_{1}\text{H} (deuterium) and 13H {}^{3}_{1}\text{H} (tritium).
TermDefinitionExample
IsotopesAtoms having the same number of protons but different numbers of neutrons11H {}^{1}_{1}\text{H}, 12H {}^{2}_{1}\text{H}, 13H {}^{3}_{1}\text{H}; also 23He {}^{3}_{2}\text{He} and 24He {}^{4}_{2}\text{He}
IsobarsAtoms having the same mass number AA13H {}^{3}_{1}\text{H} and 23He {}^{3}_{2}\text{He}
IsotonesAtoms having the same number of neutrons but different atomic number13H {}^{3}_{1}\text{H} and 24He {}^{4}_{2}\text{He}
  • Isotopes have the same chemical properties, since chemistry depends only on ZZ.

Units for measuring masses

  • In kilogram: me=9.109383×10−31 kgm_e = 9.109383\times10^{-31}\ \text{kg}, mp=1.672623×10−27 kgm_p = 1.672623\times10^{-27}\ \text{kg}, mn=1.674927×10−27 kgm_n = 1.674927\times10^{-27}\ \text{kg}. The kilogram is an inconvenient unit at this scale.
  • Unified atomic mass unit: one u is one twelfth of the mass of a neutral carbon atom of atomic mass 1212 in its lowest electronic state, and 1 u=1.6605402×10−27 kg1\ \text{u} = 1.6605402\times10^{-27}\ \text{kg}. In this unit me=0.00055 um_e = 0.00055\ \text{u}, mn=1.008665 um_n = 1.008665\ \text{u}, and the hydrogen atom is 1.007825 u1.007825\ \text{u} (the free proton is 1.00728 u1.00728\ \text{u}).
  • Energy equivalent: by E=mc2E = mc^2 a mass may be quoted in eV/c2\text{eV}/c^2, with 1 u=931.5 MeV/c21\ \text{u} = 931.5\ \text{MeV}/c^2. Then me=0.511 MeV/c2m_e = 0.511\ \text{MeV}/c^2, mp=938.28 MeV/c2m_p = 938.28\ \text{MeV}/c^2 and mn=939.57 MeV/c2m_n = 939.57\ \text{MeV}/c^2.

Size of nuclei

  • Not all nuclei are the same size; the size depends on the number of nucleons, i.e. on the mass number AA. Experimentally the radius RXR_X of a nucleus XX is

RX=R0A1/3,R0=1.2×10−15 mR_X = R_0A^{1/3},\qquad R_0 = 1.2\times10^{-15}\ \text{m}

  • So the nuclear volume 43πRX3=43πR03A\dfrac{4}{3}\pi R_X^3 = \dfrac{4}{3}\pi R_0^3A is directly proportional to AA, and R1R2=(A1A2)1/3\dfrac{R_1}{R_2} = \left(\dfrac{A_1}{A_2}\right)^{1/3}.

Density of a nucleus

  • Take mm as the average mass of a nucleon, the proton and neutron masses being nearly equal. The mass of the nucleus is then mAmA and the density is

ρ=mA43πRX3=3mA4πRX3\rho = \dfrac{mA}{\dfrac{4}{3}\pi R_X^3} = \dfrac{3mA}{4\pi R_X^3}

  • Substituting RX=R0A1/3R_X = R_0A^{1/3}, so that RX3=R03AR_X^3 = R_0^3A, the AA cancels:

ρ=3m4πR03=constant\rho = \dfrac{3m}{4\pi R_0^3} = \text{constant}

  • Hence the density of a nucleus does not depend on its mass number and is the same for all nuclei. Putting in the numbers, ρ=2.3×1017 kg m−3\rho = 2.3\times10^{17}\ \text{kg m}^{-3}.
  • This is enormous: osmium, the densest known element, has a density of only 2.2×104 kg m−32.2\times10^{4}\ \text{kg m}^{-3}, smaller than nuclear density by thirteen orders of magnitude.
  • Worked check: for 70Ge {}^{70}\text{Ge} of mass 69.924 u69.924\ \text{u}, R=1.2×10−15×701/3=4.945×10−15 mR = 1.2\times10^{-15}\times70^{1/3} = 4.945\times10^{-15}\ \text{m} and ρ=3M4πR3=2.292×1017 kg m−3\rho = \dfrac{3M}{4\pi R^3} = 2.292\times10^{17}\ \text{kg m}^{-3}.

Nuclear forces

  • Of the four fundamental forces, the one that determines the structure of the nucleus is the strong force, also called the nuclear force. It acts between protons and neutrons and is mostly attractive.
  • The protons in a nucleus repel one another electrostatically. The nuclear force is much stronger than the electrostatic force at the distances between nucleons in a typical nucleus, so it overcomes the repulsion and holds the nucleus together, making it stable.
  • Properties, as the board wants them listed:
  • It is the strongest force among subatomic particles, about 5050 to 6060 times stronger than the electrostatic force.
  • Its range is only about a few fm, and the force becomes negligible when two nucleons are separated by more than that — quite unlike the electrostatic and gravitational forces, whose range is infinite.
  • It is charge independent: the force between two neutrons at a given separation is the same as that between two protons, or between a neutron and a proton, at the same separation.
  • The nuclear force is not yet well understood; only these properties are known and expected in an answer.