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CalibratePhysics

2.8

Equation of Continuity

Mechanical Properties of Fluids · Maharashtra HSC

Theory

The physical idea

Consider a steady flow of an incompressible fluid through a tube whose cross section changes, with a wide section of area A1A_{1} and a narrow section of area A2A_{2}. For a steady flow the velocity of a particle is constant at a given point but may vary from point to point. A particle has to move faster in the narrower section, where there is less space, to accommodate the particles behind it; entering a wider section it slows down because there is more space. Because the fluid is incompressible, the particles move faster through a narrow section and slow down through a wider section — if the fluid did not speed up in a narrow region it would have to be compressed to fit into the narrow space.

Diagram to draw

A tube of flow of varying cross section. Mark a wider section of area A1A_{1} at point A, cut by the surface EFGH, and a narrower section of area A2A_{2} at point B, cut by the surface PQRS. Show velocities v1v_{1} and v2v_{2} at the two sections. All the fluid is confined to the tube of flow, so no fluid can leave or enter through its walls.

Derivation

All the fluid that passes through a tube of flow must pass through any cross section that cuts the tube. Matter is neither created nor destroyed within the region between A1A_{1} and A2A_{2}, so the mass of fluid in that region is constant over time: if a mass mm enters at A1A_{1}, an equal mass must leave at A2A_{2}.

Let the fluid cross the section EFGH at A with speed v1v_{1} in a time interval Δt\Delta t. The mass entering through this cross section is ρA1v1Δt\rho A_{1}v_{1}\Delta t.

Let the fluid cross the section PQRS of area A2A_{2} at B with speed v2v_{2} in the same interval Δt\Delta t. The mass leaving through this cross section is ρA2v2Δt\rho A_{2}v_{2}\Delta t.

Since the fluid is incompressible, the mass entering at A equals the mass leaving at B:

ρA1v1Δt=ρA2v2Δt\rho A_{1}v_{1}\Delta t = \rho A_{2}v_{2}\Delta t

A1v1=A2v2orAv=constantA_{1}v_{1} = A_{2}v_{2} \qquad\text{or}\qquad Av = \text{constant}

This is the equation of continuity in fluid dynamics. It states that the volume rate of flow of an incompressible fluid in a steady flow is the same throughout the flow, and it is an expression of the conservation of mass.

Flux

  • Av=dVdtAv = \dfrac{dV}{dt} is the volume rate of flow, the volume of fluid per unit time passing through any cross section of the tube of flow. It is called the volume flux.
  • ρdVdt=dmdt\rho\dfrac{dV}{dt} = \dfrac{dm}{dt} is called the mass flux.
  • The basic unit of measuring flow is the cusec, one cubic foot per second (28.317 litre per second).

Standard results

  • A1v1=A2v2A_{1}v_{1} = A_{2}v_{2}, i.e. AvAv = constant, for a steady flow of an incompressible fluid.
  • v∝1Av \propto \dfrac{1}{A}; for a circular pipe A=πd2/4A = \pi d^{2}/4, so v∝1d2v \propto \dfrac{1}{d^{2}} and d∝1vd \propto \dfrac{1}{\sqrt{v}}.
  • Volume flux =Av= Av; mass flux =ρAv= \rho A v.