Chapter 11
Dual Nature of Radiation and Matter
CBSE · 7 subtopics
Formula SheetEvery formula this chapter can be examined on, in one table.
Constants and conversions CBSE expects you to know
Quantity Value to quote Other useful form Planck's constant J s eV s Speed of light m s Product J m eV nm, i.e. eV Å Electron charge C eV J Electron mass kg kg Specific charge C kg same for all cathode materials Proton mass kg - eV nm is the single most time-saving number in this chapter: photon energy in eV with in nm. Some CBSE keys use eV nm (from eV s); either is accepted.
- Å m nm. So in eV with in Å.
Electron emission
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Experimental study of the photoelectric effect
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Einstein's photoelectric equation
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Particle nature of light: the photon
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Wave nature of matter
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Short NotesThe chapter subtopic by subtopic, in the textbook's own order.7 subtopics
- 1Electron Emission1 board question
- 2Photoelectric Effect2 board questions
- 3Experimental Study of Photoelectric Effect20 board questions
- 4Photoelectric Effect and Wave Theory of Light1 board question
- 5Einstein's Photoelectric Equation: Energy Quantum of Radiation26 board questions
- 6Particle Nature of Light: The Photon5 board questions
- 7Wave Nature of Matter20 board questions
The whole chapter in brief
11.1 Introduction: how the electron was found
- Discharge of electricity through gases at low pressure (about mm of mercury) produces cathode rays. Crookes (1870) discovered them; he suggested in 1879 that they are streams of fast negatively charged particles.
- J. J. Thomson (1897) applied mutually perpendicular electric and magnetic fields across a discharge tube and measured the speed and the specific charge of these particles. Speeds came out as to ; the accepted value of is C kg.
- was found to be independent of the cathode material and of the gas in the tube — proof that these particles are universal constituents of matter. Thomson named them electrons and received the 1906 Nobel Prize.
- Millikan's oil-drop experiment (1913) showed that the charge on a drop is always an integral multiple of C, so electric charge is quantised. Knowing and gives the electron mass kg.
- Roentgen discovered X-rays in 1895. Particles emitted by UV-irradiated metals and by hot metals were found to have the same as cathode rays — the same particle in every case.
Electron emission and work function
- Metals have free electrons, but they cannot leave the surface: an escaping electron leaves the surface positively charged, and is pulled back.
- Work function : the minimum energy required by an electron to escape from the metal surface. Measured in eV; eV J. It depends on the metal and on the nature of its surface.
- Three ways of supplying that energy:
| Process | Energy source | Example |
|---|---|---|
| Thermionic emission | heating the metal | cathode of a vacuum tube |
| Field emission | a very strong field, about V m | spark plug |
| Photoelectric emission | light of suitable frequency | photocell |
Photoelectric effect: the discovery
- Photoelectric effect: the emission of electrons from a metal surface when light of suitable frequency falls on it. The emitted electrons are called photoelectrons.
- Hertz (1887): high-voltage sparks across his detector loop were enhanced when the emitter plate was illuminated by ultraviolet light from an arc lamp.
- Hallwachs (1888): a negatively charged zinc plate connected to an electroscope lost its charge under UV light; an uncharged plate became positively charged; a positively charged plate became more positive. Conclusion: negatively charged particles are emitted.
- Lenard (1886–1902): UV light on the emitter plate of an evacuated tube with two electrodes drove a current; the current stopped the instant the light was stopped.
- Below a certain minimum frequency — the threshold frequency , characteristic of the emitter material — nothing is emitted, however intense the light.
- Zinc, cadmium and magnesium respond only to ultraviolet light. The alkali metals lithium, sodium, potassium, caesium and rubidium are sensitive even to visible light.
The experimental arrangement
- An evacuated glass or quartz tube contains a photosensitive plate C (the emitter/cathode) and a metal plate A (the collector/anode). The quartz window W lets ultraviolet light through.
- Monochromatic light from source S passes through W onto C. Electrons emitted from C are collected by A.
- A battery with a sliding contact sets the potential difference between C and A; a commutator reverses the polarity, so A can be made positive or negative with respect to C.
- A voltmeter reads the plate potential; a microammeter reads the photocurrent.
- The frequency is changed with coloured filters; the intensity is changed by moving the source nearer or further away.
The three graphs CBSE asks for
- Photocurrent versus intensity (collector positive, frequency and potential fixed): a straight line through the origin. Photocurrent is directly proportional to intensity, because the number of photoelectrons per second is proportional to the number of photons per second.
- Photocurrent versus collector plate potential: as the positive potential of A is raised, the current rises and then flattens at the saturation current, when every emitted electron reaches A. As A is made negative, the current falls and drops sharply to zero at the stopping potential . For a fixed frequency and increasing intensities : three curves of the same shape, all cutting the potential axis at the same , saturating at successively higher currents. For a fixed intensity and increasing frequencies : three curves saturating at the same current, but cutting the potential axis at successively more negative stopping potentials.
- Stopping potential versus frequency: a straight line, . Slope , the same for every material; it meets the -axis at and the -axis at . Two different metals give two parallel lines; the line further to the right has the greater , hence the greater work function.
- Related straight lines: versus has slope and -intercept ; versus has slope ; versus has slope .
The four experimental observations (learn this list)
- For a given material and a frequency above threshold, the photocurrent is directly proportional to the intensity of the incident light.
- For a given material and frequency, the saturation current is proportional to intensity, while the stopping potential is independent of intensity.
- For a given material there is a threshold frequency below which no emission occurs, however intense the light. Above , the stopping potential — equivalently — increases linearly with frequency and is independent of intensity.
- Photoelectric emission is instantaneous: the time lag is about s or less, even for very dim light.
Definitions worth writing verbatim
- Threshold frequency: the minimum frequency of incident radiation below which photoelectric emission does not take place, however large the intensity of light may be.
- Stopping potential: the minimum negative (retarding) potential given to the collector plate with respect to the emitter at which the photoelectric current becomes zero.
- Saturation current: the maximum photocurrent, reached when all the photoelectrons emitted per second are collected.
- Intensity, in the photon picture: the light energy — the number of photons multiplied by the energy of each photon — incident per unit area per unit time. SI unit W m.
- Work function: the minimum energy required by an electron to escape from the metal surface.
Why the wave theory fails
| Wave theory predicts | Experiment shows |
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| should rise with intensity, since the field amplitude rises | is completely independent of intensity |
| Any frequency should work if the beam is intense enough — no threshold | Nothing is emitted below , however intense the beam |
| Energy is spread over the wavefront, so an electron must accumulate it over hours | Emission is instantaneous, within s |
- The stopping potential — independent of intensity, dependent on frequency — is the crucial discriminator between the wave picture and the photon picture.
Einstein's photoelectric equation (1905)
- Radiation energy comes in discrete quanta, each of energy . In photoemission a single electron absorbs a single quantum, all of it, at once.
- It explains all four observations at once: is linear in and free of intensity; emission needs , i.e. ; intensity fixes the number of quanta and hence the current; and one-photon-one-electron absorption is instantaneous.
- Electrons deeper inside the metal are more tightly bound and emerge with less than , so photoelectrons come out with a spread of energies from to .
- Millikan set out (1906–1916) to disprove the equation, measured the slope of the – line for sodium, obtained J s in agreement with Planck's value, and ended up proving it.
The photon picture: five properties
- In its interaction with matter, radiation behaves as if made of particles called photons.
- Each photon has energy , momentum , and speed .
- All photons of a given frequency carry the same energy and momentum whatever the intensity. Raising the intensity increases only the number of photons crossing unit area per second.
- Photons are electrically neutral and are not deflected by electric or magnetic fields.
- In a photon-particle collision, total energy and total momentum are conserved, but the number of photons need not be — a photon may be absorbed or created.
- Compton's 1924 experiment on the scattering of X-rays by electrons confirmed the particle behaviour of light. Einstein received the 1921 Nobel Prize (partly for the photoelectric effect) and Millikan the 1923 Nobel Prize.
Wave nature of matter: de Broglie
- de Broglie's argument (1924): nature is symmetrical, and matter and radiation are the two basic entities; since radiation shows a dual character, matter should too. So a wave should be associated with every moving material particle.
- The left side is a wave attribute, the right side a particle attribute, and Planck's constant links them — the dual nature of matter is contained in this one relation.
- The de Broglie wavelength is independent of the charge and the nature of the particle; it depends only on the momentum.
- Consistency with radiation: for a photon , so , exactly the wavelength of the radiation.
- Why we do not see matter waves: a kg ball at m s has kg m s and m — far beyond measurement. An electron at m s has nm, comparable to X-ray wavelengths and to the spacing of atomic planes in a crystal, so it is measurable.
- The phase velocity of a matter wave has no physical significance; the group velocity does, and equals the velocity of the particle.
Standard ratio results
| Situation | Result |
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| Same speed | |
| Same kinetic energy | |
| Same accelerating potential | |
| Proton and -particle, same | |
| Deuteron and -particle, same | |
| Proton and -particle, same | |
| Proton and deuteron, same speed | |
| Proton and electron, same speed | |
| Two fragments of a body at rest | (equal and opposite momenta) |
Numbers CBSE reuses
| Metal | Work function (eV) | Threshold wavelength (nm) |
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| Caesium Cs | ||
| Potassium K | ||
| Sodium Na | ||
| Calcium Ca | ||
| Molybdenum Mo | ||
| Nickel Ni |
- Board papers have also quoted Na as eV and K as eV in one 2018 question; always use the value printed in the paper, not a remembered one.
Traps that cost marks
- Stopping potential depends on frequency and on the material only. Doubling the intensity, or moving the lamp closer, changes nothing about or — only the current changes. This single point is examined nearly every year.
- Moving a source closer or further changes intensity, not frequency. A metal that would not emit still will not emit.
- Threshold is a condition on frequency, so on wavelength it reverses: emission needs but . A longer wavelength is a lower frequency.
- "Greater threshold frequency" means "greater work function" and "smaller threshold wavelength". Keep the three straight.
- The slope of the – line is and is the same for all metals. Only the intercept changes with the material. Do not say the slope depends on the metal.
- Do not write "the kinetic energy of photoelectrons is ". It is the maximum kinetic energy; electrons emerge with a spread of energies from zero up to that value, because they are not all equally bound.
- Photocurrent is proportional to intensity, not to frequency; is proportional to frequency (linearly, with an offset), not to intensity. Swapping these is the classic lost mark.
- is linear in but not proportional to it: doubling gives , which is more than .
- in joule equals in joule; if is in volt then in eV is the same number. Do not multiply by twice.
- Work function must be converted to joule before dividing by , or else use eV s throughout. Mixing units here wrecks the answer.
- de Broglie wavelength applies to every moving particle, not only to charged ones, and does not depend on charge. But does, because that route uses .
- Do not use for a neutral particle or for a particle whose kinetic energy was not acquired from an accelerating potential.
- Å is for an electron only. Do not apply it to protons or alpha particles.
- A photon has zero rest mass but non-zero momentum ; never write for a photon.
- Photons are neutral, so they are not deflected by electric or magnetic fields — a favourite one-mark statement.
- On a versus graph the curve is a rectangular hyperbola, not a straight line, since .
- In the photocurrent versus potential graph, remember the current is not zero at zero potential: some electrons reach the collector on their own kinetic energy. The curve meets the axis at the negative stopping potential.
- State intensity in the photon picture as energy per unit area per unit time, and give the unit W m when asked for it.
Solved Numerical ExamplesWorked numericals to attempt first, each with a hint before the full solution.Coming soon
These are being added chapter by chapter. They are solved numericals from the prescribed book and the reference guides — not previous board questions, which live under Practice — so that you can work through the method before meeting it in a real paper.
Important DerivationsEvery derive / obtain / prove question in this chapter.7
- 1Derivation 1The figure shows versus graph for photoelectrons emitted from a surface, where is the maximum speed of electrons and is the wavelength of incident radiation (a straight line making angle with the axis, with a positive intercept on the axis). Using this graph and Einstein's photoelectric equation, obtain the expression for Planck's constant and the work function of the surface.
Asked in: CBSE Class 12 Physics — SA · 2023 · Section B, 2 marks
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Einstein's equation: This is linear in with slope , giving . The line intersects the axis (where ) at , the threshold-wavelength reciprocal, where . Substituting the value of found above: , where is the graph's intercept on the axis.
- 2Derivation 2The maximum kinetic energy of the photoelectrons emitted is doubled when the wavelength of light incident on the photosensitive surface changes from to . Deduce expressions for the threshold wavelength and work function of the metal surface in terms of and .
Asked in: CBSE Class 12 Physics — SA · 2020 · Section C, 3 marks
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For case I: For case II: Substituting (i) into (ii): Work function,
- 3Derivation 3Write Einstein's photoelectric equation and mention which important features in photoelectric effect can be explained with the help of this equation. The maximum kinetic energy of the photoelectrons gets doubled when the wavelength of light incident on the surface changes from to . Derive the expressions for the threshold wavelength and work function for the metal surface.
Asked in: CBSE Class 12 Physics — SA · Delhi 2015, Cr · Section C, 3 marks
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Einstein's photoelectric equation: Features explained: existence of threshold frequency (no emission below it, regardless of intensity), instantaneous emission, and depending only on frequency (not intensity) while photocurrent depends only on intensity (not frequency, above threshold). Same numerical derivation as Q40/Q49 pattern (Q40 above): for wavelength , ; for (giving ), . Eliminating : Also Work function:
- 4Derivation 4(a) Write the important properties of photons which are used to establish Einstein's photoelectric equation. (b) Use this equation to explain the concept of (i) threshold frequency and (ii) stopping potential.
Asked in: CBSE Class 12 Physics — SA · AI 2015, U · Section C, 3 marks
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(a) (i) In the interaction of photons with free electrons, the entire energy of the photon is absorbed. (ii) Energy of a photon is directly proportional to frequency; intensity of incident radiation depends on the number of photons falling per unit area per unit time for a given frequency. (iii) In a photon-electron collision, total energy and total momentum remain conserved. Einstein's equation: . (b) (i) Einstein's photoelectric equation: according to Einstein, when light is incident on a metal surface, incident photons are absorbed completely by valence electrons of atoms on its surface. Energy of each photon is partially utilized by an electron to become free of its "work function" , and the rest provides the maximum kinetic energy to the photoelectron, i.e. . The minimum value of the frequency of incident radiation below which photoelectric emission stops (i.e. kinetic energy of photoelectron is zero) is called threshold frequency, . (ii) When the work done by the collecting-electrode potential on a photoelectron equals its maximum kinetic energy, that electrode potential is known as the stopping potential, .
- 5Derivation 5The wavelength of a photon and the de Broglie wavelength of an electron have the same value. Show that the energy of a photon is times the kinetic energy of the electron, where , and have their usual meaning.
Asked in: CBSE Class 12 Physics — SA · Foreign 2016, An · Section B, 2 marks
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de Broglie wavelength of electron: Kinetic energy of electron: Energy of photon of the same wavelength : Dividing (ii) by (i): , as required.
- 6Derivation 6Obtain an expression for the ratio of the accelerating potentials required to accelerate a proton and an -particle to have the same de-Broglie wavelength associated with them.
Asked in: CBSE Class 12 Physics — SA · AI 2019 · Section C, 3 marks
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. Let proton () and -particle () have the same .
- 7Derivation 7(a) Explain the de-Broglie argument to propose his hypothesis. Show that de-Broglie wavelength of a photon equals the wavelength of electromagnetic radiation. (b) If deuterons and an alpha particle are accelerated through the same potential, find the ratio of the associated de-Broglie wavelengths of the two.
Asked in: CBSE Class 12 Physics — SA · 2020-21, An · Section C, 3 marks · CBSE sample question
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(a) De Broglie reasoned that nature is symmetrical, and that the two basic physical entities of the universe — matter and radiation — should therefore also be symmetrical in nature. If radiation exhibits a dual (wave and particle) character, matter should too. This led him to propose that a wave of wavelength is associated with every moving material particle, called the de Broglie or matter wave. For a photon: momentum (from ). Substituting into the de Broglie relation, , which is exactly the wavelength of the electromagnetic radiation of frequency — confirming consistency between the two pictures. (b) . Deuteron: ; alpha particle: , (since and ).
Finished revising this chapter? Practise Dual Nature of Radiation and Matter →