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CalibratePhysics

1.4

Basic Properties of Electric Charge

Electric Charges and Fields · CBSE

Theory

Point charge

If the size of a charged body is very small compared with the distances involved, the body is treated as a point charge, with all its charge concentrated at one point in space. Coulomb's law and the point-charge field formula are stated for such charges.

The three basic properties

Charge has three basic properties: additivity, conservation and quantisation. A 3-mark question asking you to state and explain them expects one clean statement plus one illustration each.

Additivity of charge

  • The total charge of a system containing q1,q2,…,qnq_1, q_2, \ldots, q_n is the algebraic sum q1+q2+⋯+qnq_1+q_2+\cdots+q_n, signs included.
  • Charge has magnitude but no direction: charges add like real numbers, so charge is a scalar, like mass.
  • The one difference from mass: mass is always positive, whereas charge may be positive or negative, so signs must be carried through.
  • Worked illustration from NCERT: a system of five charges +1,+2,−3,+4,−5+1, +2, -3, +4, -5 in arbitrary units has total charge (+1)+(+2)+(−3)+(+4)+(−5)=−1(+1)+(+2)+(-3)+(+4)+(-5) = -1 in the same unit.

Conservation of charge

  • The total charge of an isolated system remains unchanged with time. Charges may be redistributed among the bodies of the system by their interactions, but the algebraic total is constant.
  • When two bodies are rubbed, what one gains the other loses — no charge is created or destroyed, only transferred.
  • Charged particles themselves may be created or destroyed, but only in equal and opposite pairs. A neutron turning into a proton and an electron creates charges +e+e and −e-e; the total is zero before and after.
  • Conservation has been established experimentally.

Quantisation of charge

  • All free charges are integral multiples of a basic unit ee: q=neq = ne, with nn any integer, positive, negative or zero.
  • ee is the magnitude of the charge on an electron or a proton. By convention the electron carries −e-e, the proton +e+e.
  • e=1.602192×10−19 Ce = 1.602192\times10^{-19}\,\text{C}, taken as 1.6×10−19 C1.6\times10^{-19}\,\text{C} in numericals.
  • Why it must hold: if a body contains n1n_1 electrons and n2n_2 protons, its charge is n2e+n1(−e)=(n2−n1)en_2e+n_1(-e) = (n_2-n_1)e, and the difference of two integers is an integer.
  • Quantisation was first suggested by Faraday's experimental laws of electrolysis and was demonstrated experimentally by Millikan in 1912.
  • When quantisation may be ignored: at the macroscopic level a charge of 1 μC1\,\mu\text{C} is about 101310^{13} electronic charges, so the step size ee is invisible and charge appears continuous — like a dotted line seen from far away. At the microscopic level, where charges are only tens or hundreds of ee, they appear in discrete lumps and quantisation cannot be ignored.

Units of charge

  • The SI unit is the coulomb (C), defined through the ampere: one coulomb is the charge flowing through a wire in 1 s1\,\text{s} when the current is 1 A1\,\text{A}.
  • About 6×10186\times10^{18} electrons carry a charge of −1 C-1\,\text{C}, so the coulomb is a very large unit for electrostatics; the practical units are 1 μC=10−6 C1\,\mu\text{C} = 10^{-6}\,\text{C} and 1 mC=10−3 C1\,\text{mC} = 10^{-3}\,\text{C}.
  • NCERT's estimate: if 10910^{9} electrons leave a body every second, accumulating 1 C1\,\text{C} on another body takes about 200200 years.

How CBSE examines this section

  • Charge transferred when a body gains nn electrons is −ne-ne. A body carrying +1 C+1\,\text{C} which gains 5×10185\times10^{18} electrons picks up −5×1018×1.6×10−19=−0.8 C-5\times10^{18}\times1.6\times10^{-19} = -0.8\,\text{C}, so its net charge becomes 1−0.8=+0.2 C1-0.8 = +0.2\,\text{C}.
  • Spheres touched together and separated: test the offered answers twice over. First, the algebraic sum of the final charges must equal the algebraic sum of the initial charges (conservation). Second, every final charge must be an integral multiple of ee (quantisation) — an option offering +3.5e+3.5e or +5.5e+5.5e is ruled out even when its total is right.
  • For +3e+3e, +5e+5e and −3e-3e brought into simultaneous contact, the total is +5e+5e, so only sets summing to 5e5e with integral multiples of ee, such as +6e,+6e,−7e+6e, +6e, -7e, are possible.

Numericals

Every numerical set on this subtopic. Full working is at the end of the page.

  1. 1

    In an experiment, three microscopic latex spheres are sprayed into a chamber and became charged with charges +3e+3e, +5e+5e and −3e-3e respectively. All the three spheres came in contact simultaneously for a moment and got separated. Which one of the following are possible values for the final charge on the spheres?

    • (a)

      +5e,−4e,+5e+5e, -4e, +5e

    • (b)

      +6e,+6e,−7e+6e, +6e, -7e

    • (c)

      −4e,+3.5e,+5.5e-4e, +3.5e, +5.5e

    • (d)

      +5e,−8e,+7e+5e, -8e, +7e

    1 markCBSE Class 12 Physics — Multiple Choice · Term I 2021-22, U · Section A, 1 markAnswer 1 ↓
  2. 2

    An object has charge of 1 C1\,\text{C} and gains 5.0×10185.0\times10^{18} electrons. The net charge on the object becomes

    • (a)

      −0.80 C-0.80\,\text{C}

    • (b)

      +0.80 C+0.80\,\text{C}

    • (c)

      +1.80 C+1.80\,\text{C}

    • (d)

      +0.20 C+0.20\,\text{C}

    1 markCBSE Class 12 Physics — Multiple Choice · Term I 2021-22, R · Section A, 1 markAnswer 2 ↓

Answers & Solutions

Work the questions above first, then check yourself here. Each answer is set out the way it should be written in the paper.

  1. Total charge, q=q1+q2+q3=3e+5e−3e=5eq = q_1+q_2+q_3 = 3e+5e-3e = 5e. Since charge is conserved, the sum of final charges must also equal 5e5e: (a) q=5e−4e+5e=6eq = 5e-4e+5e = 6e — sum wrong. (b) q=6e+6e−7e=5eq = 6e+6e-7e = 5e — sum correct, and all are integral multiples of ee. (c) q=−4e+3.5e+5.5e=5eq = -4e+3.5e+5.5e = 5e — sum correct, but by quantisation of charge, 3.5e3.5e and 5.5e5.5e are not possible (charge is always an integral multiple of ee). (d) q=5e−8e+7e=4eq = 5e-8e+7e = 4e — sum wrong.

  2. Initial charge, q=1 Cq = 1\,\text{C}; number of electrons gained, n=5×1018n = 5\times10^{18} Charge transferred (gained electrons are negative), Q=−ne=−5×1018×1.6×10−19=−0.8 CQ = -ne = -5\times10^{18}\times1.6\times10^{-19} = -0.8\,\text{C} Net charge on the object =q+Q=1−0.8=0.2 C= q+Q = 1-0.8 = 0.2\,\text{C}